Question

Limit help
medal and fan....

Answer 1

ok

Answer 2

Epsilon method?

Answer 3

I've used this maybe once, but I don't know much about analysis let me tag someone that maybe able to help @ganeshie8

Answer 4

Note that this question has two parts. In the first part you are asked to find the limit of the given function y = 3 - 2x as x approaches x0 = 3. As this happens, the function value y approaches what limit? This part is very straightforward, because y = 3 - 2x is a polynomial and is thus defined for all x. Because of this, we can simply substitute x0 = 3 for x in y = 3 - 2x. The resulting value is the limit of the function as x approaches 3.

Answer 5

they want to know how close to 3 do you have to get so that if x is within that tolerance, the function will be with .02 of the actual value.

|f(x) - L|<.02 => |3-2x - (-3)| < .02 so

-.02 < 3 - 2x + 3 < .02 => -.02 < 6-2x < .02

-6.02 < -2x < -5.98

5.98/2 < x < 6.02

2.99 < x < 3.01

so d < .01 (d being delta)