Question

http://prntscr.com/955xvk

Answer 1

yeah i dont understand this sorry

Answer 2

@imqwerty

Answer 3

we have been given\[\frac{ x }{ a }=\frac{ y }{ b }=\frac{ z }{ c }\]and we have to prove\[\frac{ x^3 }{ a ^3} \times\frac{ y^3 }{ b^3 }+\frac{ z }{ c }=\frac{ xyz }{ abc }\]right?

Answer 4

correction-\[\frac{ z^3 }{ c^3}\]

Answer 5

¿?

Answer 6

thats really confusing

Answer 7

yes @imqwerty

Answer 8

ok :)

Answer 9

Suppose\[\frac{ x }{ a }=\frac{ y }{ b }=\frac{ z }{ c }=\alpha\]so we have to prove\[\alpha^3 \times \alpha^2+\alpha^3=\alpha^3\]but we have\[\alpha^3(\alpha^3+1)=\alpha^3\]\[\alpha^3+1=1\]\[\alpha =0\]clearly the ques has some fault or something
its not general
it will hold true only if x=y=z=0