Question

What is the solution to the system of equations?

Use the linear method.


5x+2y=-4
-3x+2y=12

A. (-2,3)
B. (4,0)
C. (0,-2)
D. (2,-7)

Answer 1

@Surana

Answer 2

First arrange both equations using y=mx+c

Answer 3

\[5x+2y=-4-First~eqn\]First subtract both sides by 5x
Then divide both sides by 2

Answer 4

\[5x-5x+2y=-5x-4\]

Answer 5

\[2y=-5x-4\]

Answer 6

\[\frac{ 2y }{ 2 }=\frac{- 5x }{ 2 }+\frac{ -4 }{ 2 }\]

Answer 7

\[y=-\frac{ 5 }{ 2 }x-2\]

Answer 8

\[-3x+2y=12-Second~eqn\]

Answer 9

Add 3x on both sides
Then divide both sides by 2

Answer 10

\[-3x+3x+2y=3x+12\]

Answer 11

\[2y=3x+12\]

Answer 12

\[\frac{ 2y }{ 2 }=\frac{ 3x }{ 2 }+\frac{ 12 }{ 2 }\]

Answer 13

\[y=\frac{ 3 }{ 2 }x+6\]

Answer 14

Now substitute the first eqn into the second eqn to find the value of x.

Answer 15

\[y=-\frac{ 5 }{ 2 }x-2-First~eqn\]\[y=\frac{ 3 }{ 2 }x+6-Second~eqn\]

Answer 16

\[-\frac{ 5 }{ 2 }x-2=\frac{ 3 }{ 2 }x+6\]

Answer 17

First subtract 3x/2 on both sides

Answer 18

\[-\frac{ 5 }{ 2 }x-\frac{ 3 }{ 2 }x-2=6\]Then add 2 on both sides

Answer 19

\[-\frac{ 5 }{ 2 }x-\frac{ 3 }{ 2 }x=6+2\]

Answer 20

\[\frac{ -5x-3x }{ 2 }=8\]Then multiply oth sides by 2

Answer 21

both*

Answer 22

\[-8x=16\]Then divide -8 on both sides

Answer 23

\[x=-2\]

Answer 24

Nowsubstitute x=-2 into the first equation\[y=-\frac{ 5 }{ 2 }x-2\]

Answer 25

sorry I was afk

Answer 26

\[y=-\frac{ 5 }{ 2 }(-2)-2\]

Answer 27

\[y=5-2\]\[y=?\]solve it @mc2014

Answer 28

3
So its A?

Answer 29

yes :)

Answer 30

thank you

Answer 31

you're welcome

Answer 32

I gave you a medal and I fanned you

Answer 33

thank you :)

Answer 34

np (no problem)