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PLEASE HELP The function f is continuous at x=1. If f(x)= (√(x+3)-√(3x+1))/(x-1), for x NOT = 1 k, for x=1 Then k=? 1.) 0 2.) 1 3.) (1/2) 4.)(-1/2) 5.) none of the above explanation would be greatly appreciated
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In order to find k we need to find the Lim x->1 of f(x) are you familiar with evaluating limits of the type 0/0 ?
i am not can you please explain?
have you heard of L'Hopitals's rule?
never, I'm only in ap calc ab
see there isn't a feature like this on this website but there is supposed to be a bracket on the left of (√(x+3)-√(3x+1))/(x-1), for x NOT = 1 k, for x=1
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