(Calculus, Antiderivatives) A stone is dropped from the upper observation deck of a tower, 250 m above the ground. (Assume g = 9.8 m/s2.)
The section doesn't cover this problem, so I'm doomed. :(

Question

(Calculus, Antiderivatives) A stone is dropped from the upper observation deck of a tower, 250 m above the ground. (Assume g = 9.8 m/s2.)
The section doesn't cover this problem, so I'm doomed.  :(

zenmo · Answer

attachment

ganeshie8 · Answer

what do you know about the relationship among acceleration, velocity, and displacement ?

zenmo · Answer

Nothing, I haven't taken physics yet.

ganeshie8 · Answer

they are not hard, i can teach you if you want to know

zenmo · Answer

Sure

owlcoffee · Answer

$$v=\frac{ dx }{ dt } \iff v.dt=dx \iff \int\limits_{a}^{x}v.dt=x$$

ganeshie8 · Answer

Suppose you're running at a "velocity" of 3 m/s.

How much distance would you be covering in 5 seconds ?

zenmo · Answer

15m

ganeshie8 · Answer

how did you get 15m ?

zenmo · Answer

3m/s, (assuming m= in meters) / second. 1 second=3 meters, so 3 meters x 5 seconds = 15 meters?

ganeshie8 · Answer

you have got the displacement as 15m by integrating the velocity over the time during the first 5 seconds. let me show you exactly what you did here

ganeshie8 · Answer

can you draw the graph of velocity function, $v(t) = 3$ ?

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