Question

@haleyelizabeth2017 @ganeshie8

Answer 1

\[2x^2+x+2=0\]?

Answer 2

I'm not sure. That's why I'm confused.

Answer 3

yeah i think it was just typeset poorly

Answer 4

the solution to \[ax^2+bx+c=0\] is \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] in your case \(a=2,b=1,c=2\)

Answer 5

@Smart_Owl_Student I don't appreciate you sending me rude messages. And @satellite73 so, basically I would just plug in those numbers?

Answer 6

es exactly

Answer 7

So, -1 plus over minus sqrt 1^2-4*2*2/2*2?

Answer 8

yes that is the first step