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Help Trig SinΘCosΘ+SinΘ/CosΘ+Cos^2Θ=TanΘ
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\[\frac{ Sin \theta Cos \theta + Sin \theta }{ Cos \theta + Cos ^{2} \theta }\]
= Tanx
pls help me
factoring would help
where can i begin
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then cancel
The second term in the original equation is sin theta / cos theta.
\[\frac{ab+b}{a+a^2}=\frac{b(1+a)}{a(1+a)}\] it is 100% algebra 0% trig
Factor the numerator (in which both terms have sin x); Factor the denominator (in which both terms have cos x) See if that helps.
Satellite73 and I are discussing the same approach (factoring), using different examples.
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