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OpenStudy (winsteria):
The instructor had saved $3,500 and rents an apartment for $275 monthly. He believes the point (6, 1850) would be on the equation of the line. Is he correct? Explain how to check if a point is on a line.
OpenStudy (winsteria):
@AlexandervonHumboldt2
OpenStudy (winsteria):
this is an example of the graph
OpenStudy (winsteria):
@mathmate
OpenStudy (winsteria):
anyone know?
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OpenStudy (winsteria):
@Pawanyadav
OpenStudy (anonymous):
okay so if we have 3500 and we pay 275 each month,
y-y1=m(x-x1)
y-3500=-275/1(x-0)
OpenStudy (anonymous):
so now plug in the point for x and y then solve to see if it is true
OpenStudy (anonymous):
@winsteria could you do that?
OpenStudy (winsteria):
I think if it's
y = 6
x = 1850
6-3500=-275/1(1850-0) ?
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OpenStudy (anonymous):
close, switch the x and y values
OpenStudy (winsteria):
y = 1850
x = 6
1850-3500=-275/1(6-0)
OpenStudy (anonymous):
yes now simplify both sides and see if the equation is true :) you got this
OpenStudy (pawanyadav):
Total money=3500
When he pay rent for six month=1650
He left with (3500-1650=1850)
So the point is on the line.
OpenStudy (pawanyadav):
Six month rent =6×275=1650
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