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Mathematics 23 Online
OpenStudy (amonoconnor):

Estimate the interval from -2 to 4 of the quantity x^3*dx using 3 subintervals and A) left endpoints, B) right endpoints, and C) midpoints. How do I set this up to just be evaluating only the values for one type of rectangle under the curve? Is it a matter of what numbers I set xO, x1, x2, and x3 as? Any and all help is greatly appreciated!

OpenStudy (anonymous):

from -2 to 4 has length 6

OpenStudy (anonymous):

if you divide it in to 3 parts, each will have length 2

OpenStudy (anonymous):

they will be \[-2,0,2,4\] left hand endpoints are \[-2,0,2\] right hand are \[0,2,4\]

OpenStudy (anonymous):

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OpenStudy (amonoconnor):

Right, but like, what's the formula or method for plugging that in, with a particular orientation to one side or the boxes that would be drawn into the curve? :/

zepdrix (zepdrix):

Those left endpoints are the values you use to determine the height of each rectangle. So at your first left endpoint, x=-2, The height of that rectangle will be f(-2)=(-2)^3=-8. So the area of your first rectangle is A=length*width A=-8*2

zepdrix (zepdrix):

I should have written: A=height*width That would have been more appropriate ;) lol

OpenStudy (amonoconnor):

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