In a quadrilateral ABCD, the diagonals intersect at point T. Byron has used the Alternate Interior Angles Theorem to show that angle DAC is congruent to angle BCA and that angle BAC is congruent to DCA.

Which of the following can Byron use prove that side AD is equal to side BC?

AC ≅ AC
AC ≅ DB
DB ≅ DB
TB ≅ TD

Question

In a quadrilateral ABCD, the diagonals intersect at point T. Byron has used the Alternate Interior Angles Theorem to show that angle DAC is congruent to angle BCA and that angle BAC is congruent to DCA.

Which of the following can Byron use prove that side AD is equal to side BC?

 AC ≅ AC
 AC ≅ DB
 DB ≅ DB
 TB ≅ TD

directrix · Answer

Is this quadrilateral given to be a parallelogram or some other type of special quadrilateral?

directrix · Answer

If there is a diagam, please post it.

anonymous · Answer

There isnt a diagram to go along with the question

anonymous · Answer

I would assume it is a parallelogram however

anonymous · Answer

It would be D correct? Because thats the only one that would create two triangles out of the quadrilateral and it would create side angle side postulate.

anonymous · Answer

Or is that wrong?

anonymous · Answer

|dw:1448333919042:dw|

anonymous · Answer

actually no that wouldnt be correct now that im seeing the diagram

directrix · Answer

|dw:1448334038124:dw|