Mathematics
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OpenStudy (anonymous):
FAN N MEDAL
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OpenStudy (anonymous):
ABCD is a rectangle. What is the value of x?
rectangle with length 63 m, width x m, and diagonal 65 m
2 meters
16 meters
63 meters
65 meters
OpenStudy (anonymous):
TheSmartOne (thesmartone):
|dw:1448380596592:dw|
TheSmartOne (thesmartone):
Do you know Pythagorean Theorem? :)
OpenStudy (anonymous):
i think so
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OpenStudy (anonymous):
i think the answer is 16 meters
TheSmartOne (thesmartone):
The Pythagorean Theorem is: \(\sf\Large a^2 + b^2 = c^2\)
where a and b are the legs of a right triangle
and c is the hypotenuse
OpenStudy (anonymous):
okay yes then i know what the Pythagorean theorem is
TheSmartOne (thesmartone):
So what is the hypotenuse in this question?
OpenStudy (anonymous):
i don't know
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TheSmartOne (thesmartone):
|dw:1448380995888:dw|
OpenStudy (pyxieyt):
They are looking for the value of x! You would use the Pythagorean theorem still.
\[63+?=65\]
Do you know how to find the answer?
OpenStudy (anonymous):
2
OpenStudy (pyxieyt):
Wait! That is not the answer yet!
OpenStudy (anonymous):
oh okay
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TheSmartOne (thesmartone):
@pyxieyt you're not doing it correct :/
OpenStudy (pyxieyt):
We would have to make it look like this
\[A+63^2=65^2\]
OpenStudy (pyxieyt):
Yeah I realised that :P
TheSmartOne (thesmartone):
now that's kinda correct
it has to be in the form
\(\sf\Large a^2 + b^2 = c^2\)
And after plugging in the numbers:
\(\sf \Large a^2 + 63^2 = 65^2\)
OpenStudy (pyxieyt):
Now, what would be 63x63?
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OpenStudy (pyxieyt):
What would be 65x65?
OpenStudy (anonymous):
it would be 4225 i think
TheSmartOne (thesmartone):
wha twould be 4225? :)
OpenStudy (anonymous):
65x65
OpenStudy (pyxieyt):
Okay so what is 63x63?
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OpenStudy (anonymous):
it is 3969
OpenStudy (pyxieyt):
Okay so what is 4225-3969
OpenStudy (anonymous):
256
TheSmartOne (thesmartone):
and take the squareroot of that
TheSmartOne (thesmartone):
\(\sf\sqrt{256} = ?\)
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OpenStudy (anonymous):
uhm.. 16?
TheSmartOne (thesmartone):
and that's your answer :)
OpenStudy (pyxieyt):
Yep! You got it correct!
OpenStudy (anonymous):
thank you so much both of you
OpenStudy (pyxieyt):
Good job!
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TheSmartOne (thesmartone):
Anytime! :D