Question

Solve for n: 21k – 3n + 9p > 3p + 12.

A. n > 2p + 7k – 4
B. n < 2p + 7k – 4
C. n > –4p – 7k + 4
D. n < –4p – 7k + 4

Answer 1

D

Answer 2

subtract 9p from both sides
\[21k - 3n > -6p + 12\]
Subtract 21k from both sides
\[-3n > -21k - 6p + 12\]
Divide both sides by -1 and flip the sign of the inequality
\[n < 7k + 2p - 4\]

Answer 3

It's B not D

Answer 4

Thx for the help @GabeBae

Answer 5

For the last step I typed in -1 by accident it's supposed to be -3