Question

f(x)=2x^2-4x+5 find f(-3)

Answer 1

help xD

Answer 2

trying to figure it out first, sorry x/

Answer 3

It would be a solid 3 not -3

Answer 4

really?

Answer 5

vertex Pt(-1,3)

Answer 6

x=1+sqrt(-3/2) or

x=1-sqrt(-3/2).
or i'm just confused :/ sorry

Answer 7

Put y=0 in y=2x^2-4x+5 and solve for x.

2x^2-4x+5=y. The same equation reversed for my convenience please.

2x^2-4x+5= 0, as y needs to be put to 0

2(x^2-2x)+5=0, rearranged .

2[(x-1)^2 -1}+5=0, rearranged.

2(x-1)^2-2 =-5.

2(x-1)^2=-5+2 .

2(x-1)^2=-3

(x-1)^2=-3/2

x-1= + or - sqrt(-3/2)

x=1+sqrt(-3/2) or

x=1-sqrt(-3/2).

Answer 8

" http://www.enotes.com/homework-help/how-do-find-any-x-y-intercepts-f-x-2x-2-4x-5-98403 "

Answer 9

f(-3) means x=-3
so substitute all x's for -3 and then solve
that's it!

Answer 10

but it says find @Nnesha

Answer 11

yes correct find f(-3) so they are asking what would be the value of f(-3) when x=-3

Answer 12

Can you show the work needed for the equation? @Nnesha

Answer 13

there is not much work for this
here is an example \[\rm g(x)=2\color{ReD}{x}+4\] to find g(4)
i would substitute x for 4 \[\rm g(4)=2\color{ReD}{(4)}+4\]
and then just solve the right side