Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

https://lh5.googleusercontent.com/Sh9vhl0jgDFUe3saWeGTz02ufDD4JuC7zbn25PUBzSenudNkzZ0XzipGjuZiJQPzUAIkGQ Please help What is the equation of this line?

OpenStudy (anonymous):

@EclipsedStar

OpenStudy (anonymous):

@TheSmartOne

TheSmartOne (thesmartone):

ok, first let's find the slope :)

OpenStudy (anonymous):

3x / 1y ?

TheSmartOne (thesmartone):

\(\sf\Large Slope = \frac{\color{blue}{y_2}-\color{red}{y_1}}{\color{green}{x_2}-\color{purple}{x_1}}\) Where the two points are in the form: \(\sf\Large (\color{purple}{x_1},\color{red}{y_1})~and~(\color{green}{x_2},\color{blue}{y_2})\)

TheSmartOne (thesmartone):

what is that?

OpenStudy (anonymous):

ohh nvm, its 3, -1 and 6,1

TheSmartOne (thesmartone):

the point is (3,0) and (6,1)

TheSmartOne (thesmartone):

so, what would the slope be? :)

OpenStudy (anonymous):

1/3

OpenStudy (anonymous):

3/1 or 1/3

TheSmartOne (thesmartone):

now, what is the y-intercept? look for where x = 0, and y crosses the y-axis

OpenStudy (anonymous):

y-intersept = -1?

TheSmartOne (thesmartone):

correct! :D

OpenStudy (anonymous):

:D

TheSmartOne (thesmartone):

so now we plug it into the slope-intercept form :) y = mx + b we got m = 1/3 and b = -1

OpenStudy (anonymous):

ok

TheSmartOne (thesmartone):

so what do you get? :)

OpenStudy (anonymous):

1/3*6+-1 = 1?

TheSmartOne (thesmartone):

not sure where the y and x ran away we have to keep y and x and only replace m and b y = mx + b m = 1/3 substitute that in and we get: y = (1/3)x + b b = -1 plug that in :)

OpenStudy (anonymous):

ok so its y = (1/3)x + -1? for the answer?

TheSmartOne (thesmartone):

almost there :P

TheSmartOne (thesmartone):

1/3(x) + (-1) = (1/3)x - 1 so your final answer is y = (1/3)x - 1

OpenStudy (anonymous):

ok, thanks :)

TheSmartOne (thesmartone):

Anytime! :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!