Question

Question in Comment!
Thankiez!

Answer 1

@TheSmartOne

Answer 2

First use the formula: \(\sf\Large (a^b)^c = a^{bc}\)

Answer 3

mhm?

Answer 4

so \(\sf\Large (2^2)^5 = 2^{2\times5} = 2^{??}\)

Answer 5

10

Answer 6

and now we use this formula:

\(\sf\Large \frac{a^b}{a^c}=a^{b-c}\)

Answer 7

ok, and what is that with the numbers from the equation?

Answer 8

\(\sf\Large \frac{2^{10}}{2^{16}}=a^{10-16}=2^{??}\)

Answer 9

6

Answer 10

-6*

Answer 11

and now we use this formula:

\(\sf\Large a^{-b} = \frac{1}{a^b}\)

so what is \(\sf\Large 2^{-6} = ?\)

which answer choice? :P

Answer 12

@sissyedgar :P

Answer 13

D.

Answer 14

nope, look at the last formula I gave you :P

Answer 15

riiiight...
A

Answer 16

and that's your answer :)

Answer 17

thx!