The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64
No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64
Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

Question

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64
 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64
 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

anonymous · Answer

perimeter=2(length+ width)

directrix · Answer

>> Can the length x of the rectangle can be 

I don't know what this is stating with two cans in the statement.

Check to see if you posted the problem correctly. Thanks.

thats_kyy · Answer

I did post it correctly

directrix · Answer

Add these numbers:  11 + 20 + 11 + 20 = ?   @Thats_Kyy


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