Question

how will I graph ''She is 11 meters into the race after four seconds and is only 13 meters in after 12 seconds''?

Answer 1

Time will be represented on the x-axis while progression is represented on the y-axis.

Answer 2

I know the x and y axis thing but I am trying to find the plotting and starting points

Answer 3

(x, y)
(time, meters)

Answer 4

i know the x and y but the equation what will it be

Answer 5

Well first we find the slope.

Answer 6

use your 2 sets of points (4,11) and (12,13)...and find the slope

Answer 7

Slope Formula

\[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\]

Answer 8

so what about y=mx+b

Answer 9

We can form the equation in slope-intercept form: y = mx + b

m = slope
b = y-intercept

The y-intercept is wher the line crosses the y-axis. Plug that in for b and plug in the slope for m and that is your equation.

Answer 10

(4,11)...and (12,13)

slope formula : (y2 - y1) / (x2 - x1)
(4,11)....x1 = 4 and y1 = 11
(12,13)...x2 = 12 and y2 = 13
now sub that into the slope formula and find the slope

Answer 11

And then the y-intercept is just the point where the line connects with the y-axis. That number will be 'b'.

Answer 12

so what did you get for the slope ?

Answer 13

2/8

Answer 14

and that reduces to what ?

Answer 15

1/4

Answer 16

And where does the line cross the y-axis?

Answer 17

ok...your slope(m) = 1/4

now use y = mx + b
slope(m) = 1/4
use either of your points....(4,11)...x = 4 and y = 11
now sub 1/4 in for m and 4 for x and 11 for y into y = mx + b and show me what you get.

Answer 18

your basically solving for b, your y intercept

Answer 19

y=1/4x+b or 11=1/4(4)+b