Question

I really need help on this one question
its a 8th grade one, so maybe its easy for any of you...

Answer 1

y=-4x^2-8x-14
x=-3
I HAVE TO SOLVE AND FIND A WAY FOR IT TO EQUAL -26

Answer 2

oops...caps

Answer 3

Ohh we are so offended by your caps

Answer 4

XD

Answer 5

I'm having the same exact trouble as amonoconnor XD

Answer 6

If you simply replace x by -3 and solve it, you get -26

Answer 7

\[y=-4*(-3)^2-8*(-3)-14=-26\]

Answer 8

I did work it out...im doing something wrong and I don't know what...I keep getting -46...

Answer 9

Lets take it in parts, shall we?

Answer 10

\[-4*(-3)^2\] What is this?

Answer 11

I believe its -36...

Answer 12

Yes it is. It is -36. And next \[-8*(-3)=?\]

Answer 13

didnt see square

Answer 14

but that's minus eight...its not suppose to be a negative right?

Answer 15

It is a negative. So \[-8*(-3)=24\]

Answer 16

Because you had \[-8x\] in the equation

Answer 17

but its actually 4x^-(8x)

Answer 18

So this gives us: \[-4*(-3)^2=-36\]
\[-8*(-3)=24\]
and \[-14\]
So: \[y=-36+24-14=?\]

Answer 19

It is \[y=-4x^2-8x-14\] right?

Answer 20

so that's what I was doing wrong XD

Answer 21

thanks, I finally get it

Answer 22

You're welcome :)