Question

show how to solve 3x^2+10x=8 by factoring.

Answer 1

easy:
first subtract 8 from both sides:
we get 3x^2+10x-8=0
3x^2+12x-2x-8=0
3x(x+4)−2(x+4)=0
(x+4)(3x−2)=0
now find the roots:

Answer 2

so then wouldn't I make it two separate equations: (x+4)=0 and(3x-2)=0 the solve?

Answer 3

yes yo do

Answer 4

you equal both parentheses to 0 and solve.

Answer 5

thank you

Answer 6

:)

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