Question

Help

Answer 1

@jim_thompson5910

Answer 2

@surjithayer

Answer 3

Let CD be the bisector of angle C

\[\frac{ AD }{ DB }=\frac{ AC }{ BC }\]

Answer 4

Find AC and BC and then find their ratio
and from ratio find x and y

Answer 5

you got it or not.

Answer 6

not how would i do that?

Answer 7

would AC=(AD/DB)(BC)

Answer 8

\[AC=\sqrt{\left( 2+6 \right)^2+\left( -8+2 \right)^2}=\sqrt{64+36}=10\]
\[BC=\sqrt{\left( 2-6 \right)^2+\left( -8+5 \right)^2}=\sqrt{16+9}=5\]
\[\frac{ AD }{ BD }=\frac{ AC }{ BC }=\frac{ 10 }{ 5 }=\frac{ 2 }{ 1 }\]

Answer 9

sweet is it (2, -4)

Answer 10

correct.