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For #1, this theorem is needed: Converse of the Pythagorean Theorem, which states that if the sum of the squares of the lengths of two sides of a triangle is equal to the sum of the square of the third side, then the triangle is a right triangle.
Square each side and determine if the square of the longest side = the sum of the squares of the other two sides.
Right off the bat, 4, 4, 4 cannot be sides of a right triangle. The triangle is equilateral and an equilateral triangle is equiangular. @kittymeow101 If a triangle has all 3 interior angles the same measure, can one of them be a right angle?
no they can not
Correct. So, that option is out. Looking at the 1, 2, 3 option, note that one side of a triangle cannot be shorter than the sum of the other two. 1 + 2 = 3 and there is no triangle so that option is out.
true
5.1^2 = 4.1^2 = 3.1^2 = Time to use the converse of the Pythagorean Theorem. Square each of the 3 sides of the option. Does 5.1^2 = 4.1^2 + 3.1^2 ?
Copy and paste 5.1^2 = 4.1^2 + 3.1^2 into the "box" at wolframalpha.com and here is what happens: http://www.wolframalpha.com/input/?i=5.1%5E2+%3D+4.1%5E2+%2B+3.1%5E2
Click on that and see if the "Wolf" says it is true or false.
so its not correct, which leaves use with option D
Here is the "equation" to test. Go to wolframalpha.com Paste this into the entry area: 2.5^2 = 4+1.5^2 See if that relationship is true or false.
the relationship is true which means the answer is D
The answer to #1 is what?
the answer to #1 is D
I agree.
On the second question, it is the Pythagorean theorem again. But, as the Greeks said it. The area of the square on the hypotenuse = sum of the areas of the squares on the other two sides. It amounts to this: F = D + E
Reading through the options you have to see which ones are equivalent to: F = D + E.
Think of the first option as: F - E = D Is that the same as F = D + E
option D is equivalent to F=D+E
Yes. What about option A? F - E = D Is that the same as F = D + E
no
F - E = D Add E to both sides: F = D + E
A and D are both correct options.
ok ty
You are welcome.
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