Question

Solve the following system of equations:

x − 2y = 14
x + 3y = 9


A (1, 12)
B (−1, −12)
C (12, −1)
D (12, 1)

Answer 1

Ok
Equation 1 = x − 2y = 14
Equation 2= x + 3y = 9
x−2y=14 for x:
x−2y+2y=14+2y (Add 2y to both sides)
x=2y+14

Answer 2

Now we can plug that into E2
\[\huge~\rm~\bf 2y+14 + 3y = 9\]
solve for y

Answer 3

5Y+14=9

Answer 4

good!
now subtract 14 from both sides
5y=9-14
what is 9-14=?

Answer 5

-5

Answer 6

good now divide both sides by 5
5y/5=-5/5
-5/5= ?

Answer 7

-1

Answer 8

good so y=-1

Answer 9

ok and the other is -12

Answer 10

x=2(-1)+14
x=-2+14
x=12

Answer 11

so c again

Answer 12

The answer wa obvious there was only on option that has -1 as the y value so yes it is C :) good job

Answer 13

Thank you so much again! i got a 100%

Answer 14

np =)