Mathematics
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OpenStudy (anonymous):
Write the sum using summation notation, assuming the suggested pattern continues.
-4 + 5 + 14 + 23 + ... + 131
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OpenStudy (pawanyadav):
Don't you think it's follows a pattern
Every successive term is 9 more than previous term
OpenStudy (pawanyadav):
So it's an AP series
OpenStudy (pawanyadav):
Can you find total number of terms in this series.
OpenStudy (anonymous):
i dont know how
OpenStudy (anonymous):
wait is it 15?
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OpenStudy (pawanyadav):
You know the formula to find last term of AP series
OpenStudy (anonymous):
no i dont
OpenStudy (pawanyadav):
The formula is
Last term= first term + (n-1)d
Where n=no. Of term and d=difference between two successive term
OpenStudy (anonymous):
is n 15
OpenStudy (pawanyadav):
Let's check by formula
135=-4 +(n-1)9
can you understand this
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OpenStudy (anonymous):
wait why 135 isnt it 131
OpenStudy (pawanyadav):
Just respective values are plugged
OpenStudy (pawanyadav):
Yes right
OpenStudy (anonymous):
131=-4 +(n-1)9
OpenStudy (pawanyadav):
Can you solve it for n
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OpenStudy (anonymous):
131=-4+9n-9
131=9n-13
9n=144
n=16
OpenStudy (pawanyadav):
Right
OpenStudy (pawanyadav):
Now you know the summation of AP series?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
wait
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OpenStudy (anonymous):
is it
OpenStudy (anonymous):
summation of the (-4+9n) from n equals zero to fifteen
OpenStudy (pawanyadav):
Sorry that is (n/2)[2a+(n-1)d]
OR (n/2)sum of first and last term
OpenStudy (pawanyadav):
You can do now
OpenStudy (anonymous):
what?
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OpenStudy (pawanyadav):
Sum =16/2(-4+131)
=8(128)= 1024