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Mathematics 19 Online
OpenStudy (barrelracing):

A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standard deviation were calculated. Based on the results, the exam creator claims that on the same exam, nine times out of ten, seniors will have an average score within 4% of 70%. Is the confidence interval at 90%, 95%, or 99%? What is the margin of error? Calculate the confidence interval and explain what it means in terms of the situation.

OpenStudy (barrelracing):

@Photon336

OpenStudy (barrelracing):

@mathmale

OpenStudy (barrelracing):

@caozeyuan

OpenStudy (caozeyuan):

9/10, so CL is 90%

OpenStudy (barrelracing):

that's the answer?

OpenStudy (caozeyuan):

MOe is .04

OpenStudy (caozeyuan):

MOE, sorry

OpenStudy (caozeyuan):

CI is .66-.74

OpenStudy (caozeyuan):

expalnation is just rephrase nine times out of ten, seniors will have an average score within 4% of 70%.

OpenStudy (caozeyuan):

you cold say nine times out of ten, seniors will have an average score within 66%to 74%.

OpenStudy (caozeyuan):

CL is confidence level, MOE is margin of error, CI is confidence interval, if you havent realized already

OpenStudy (caozeyuan):

It is werid to see you working on estimation for stats, but just pre calc for pure

OpenStudy (caozeyuan):

because by the time I reached estimation, I've done a year of calc

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