Question

What is the missing exponent?

Answer 1

i need help please

Answer 2

@camzzzie

Answer 3

\[(a^b)^c=a^{bc}\]
\[\frac{ a^b }{ a^c }=a^{b-c}\]

use thse properties

Answer 4

i just need the answer i have 3 mins left

Answer 5

we can't give out answers.

Answer 6

please i need to pass this

Answer 7

first lets count (8^-7)^2=8^{-7*2}=8^-14

now can you simplify \[\frac{ 8^{-5} }{ 8^{-14} }\] using the rule i gave above?

Answer 8

i dont know how to do this

Answer 9

use rule \[\frac{ a^b }{ a^c }=a^{b-c}\]

Answer 10

what does that mean

Answer 11

this is the rule

Answer 12

in your case a=8, b=-5 and c=-14

Answer 13

substitute this and solve

Answer 14

what do u mean by substitute

Answer 15

susbtiteu a, b, and c into the rule i gave and solve

Answer 16

i dont know how to do that

Answer 17

\[\frac{ 8^{-5} }{ 8^{-14} }=8^{-5+14}=?????????\]

Answer 18

o ok sorry

Answer 19

simplify what i wrote

Answer 20

i got 14 1/32768

Answer 21

no

Answer 22

can you add -5+14=????

Answer 23

calculaors will not help you at all

Answer 24

9

Answer 25

yes

Answer 26

thus your exponents is 9


\[8^9\]

Answer 27

so the answer is 8 9

Answer 28

no , it is 9

Answer 29

thank u i will tell u if u are right

Answer 30

yah u where right thankkkkkkk u so much @AlexandervonHumboldt2