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Mathematics 13 Online
OpenStudy (anonymous):

A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standard deviation were calculated. Based on the results, the exam creator claims that on the same exam, nine times out of ten, seniors will have an average score within 4% of 70%. Is the confidence interval at 90%, 95%, or 99%? What is the margin of error? Calculate the confidence interval and explain what it means in terms of the situation.

OpenStudy (anonymous):

sorry i know nothing about statistics less than nothing actually

OpenStudy (anonymous):

:( Ok

jimthompson5910 (jim_thompson5910):

how far did you get?

OpenStudy (anonymous):

well i figured out that it was a 90% interval :) being used

jimthompson5910 (jim_thompson5910):

yes because 9/10 = 90%

jimthompson5910 (jim_thompson5910):

what would the center of this confidence interval be?

OpenStudy (anonymous):

I'm not sure what center means so I'm going w/ 4% of 70%?

jimthompson5910 (jim_thompson5910):

what is the average that the teacher claims?

OpenStudy (anonymous):

9/10?

jimthompson5910 (jim_thompson5910):

no, that's the confidence level

jimthompson5910 (jim_thompson5910):

the teacher claims the average score is ______

OpenStudy (anonymous):

It doesn't say :(. All i see is that it was "the same"

jimthompson5910 (jim_thompson5910):

the teacher claims it's 70% and the error of that claim is 4% so the true average is likely from 66% to 74% notice how 66 is 4 below 70 74 is 4 above 70

jimthompson5910 (jim_thompson5910):

|dw:1448765482968:dw|

jimthompson5910 (jim_thompson5910):

|dw:1448765514479:dw|

jimthompson5910 (jim_thompson5910):

|dw:1448765542533:dw|

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