Question

If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?
2
4
9
10

Answer 1

|x|^2 = a^2 + b^2 => 13 = 3^2 + b^2 => b^2 = ?

Answer 2

9

Answer 3

@elocke: Your " |x|2 = 13 " looks strange and is ambiguous. Does that 2 represent an exponent or a multiplier or something different? If it's an exponent, write ^2 to indicate exponentiation.

@pgpilot326 : Have to ask you to defend your " |x|^2 = a^2 + b^2 " ... where did that come from? |x| refers to "the absolute value of x."

Answer 4

its not a exponent

Answer 5

no 13 - 9 = ? that's what b^2 is

Answer 6

you sure?

Answer 7

yes

Answer 8

\[\left| x \right|^2\]right?

Answer 9

no

Answer 10

@elocke: please explain what " |x|2 = 13 " means to you. Use the correct mathematical vocabulary.

Answer 11

\[\left| x \right|2\]?

Answer 12

o wait it is

Answer 13

sorry

Answer 14

@pgpilot: sorry, but |x|2 isn't any clearer. What math operation(s) is or are involved here?

Answer 15

|x| is "the absolute value of x."

What is the purpose / function of that '2' ?

Answer 16

@elocke: we're not getting anywhere. Please, would you DRAW your homework problem, using the Draw utility, below? The confusion here comes from your typing " |x|2 = 13 " ... which is not correct mathematically.

Answer 17

For example, do you mean:

\[|x|^{2}\]

Answer 18

??

Answer 19

sorry, I have to get off the 'Net, but I'll be back on later. Good luck.