Solve this system of equations using any method. 3x – y = 4 x + 2y = 13 A.(5, 11) B.(–1, 7) C.(3, 5) D.(4, 8)
Hi there! Welcome to openstduy :) So we have 2 equations 3x – y = 4 <---equation 1 x + 2y = 13 <----equation 2 I know the substitution method well enough to teach it to you so lets stick with that :)) Lets start by isolating a variable equation 2 has a variable alone lets isolate it x + 2y = 13 <----equation 2 Subtract 2y from both sides x=-2y+13 Now we have 3x – y = 4 <---equation 1 x=-2y+13 <---equation 2 Now we know the value of x let's plug equation #2 into equation #1 \[\huge~\rm~\bf 3-2y+13 – y = 4 \]Solve for y tell me what you get :)
@jojoheart if you are confused on any part please let me know!
So is it D?
Nope
B..?
Nope how bout you try to do the work? :)
Thanks I got it! It's A!
Its not A -.-
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