so i have a question i have to graph these two equations
2x+3y=1200
2x+3y=1500
I put them in slope intercept form and got
Y=-2/3x+400
y=-2/3x+500
and I am trying to graph both of them using 100, 150, 200, 250, but when i begin to graph
y=-2/3(100)+400
I start with multiplying -2/3 with 100 by turning 100 to 100/1 and i get -200/3 and dividing that i get 66.666666667 am i doing something wrong
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OpenStudy (anonymous):
for the first y-intercept equation, find positive 400 on the y-axis
OpenStudy (anonymous):
Now mark a point at positive 400
OpenStudy (anonymous):
Next, move down 2 and 3 to the right. then mark a point
OpenStudy (anonymous):
like 0,400
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
okay got it
OpenStudy (anonymous):
Great!
OpenStudy (anonymous):
wait a sec
OpenStudy (anonymous):
what about the (X) dont i have to plug that in the equation
OpenStudy (anonymous):
you're gonna find 400, mark a point on 400, then go down 2 and right 3, then mark a point. then connect the dots
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OpenStudy (anonymous):
no, the x just represents the slope
OpenStudy (anonymous):
so i can do that with the other equation as well just go up 500 and down -2 and to the right 3