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One number is six more than another number. The sum of their squares is 90. Can someone help me turn this into an equation ?
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let the 1st number by x when number is 6 more...?
oops should read, let the 1st number be x
kk
should I Put x+6 ??
great... 1st number x, 2nd number (x + 6) the next part says... the sum of their squares is 90... so \[x^2 + (x + 6)^2 = 90\] can you distribute and collect like terms..?
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No I'm just supposed to write an equation not solve
ok... so that is an equation above.... but it's not in it's simplest form
No, it's fine but THANK YOU SOOOO MUCH !!!!!!!!!!!!!!!! for your help :)
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