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Mathematics 24 Online
OpenStudy (anonymous):

WILL MEDAL A soccer team hopes to win at least 3 games for every 2 lost during the season. If there are 20 games scheduled, how many games can the team LOSE and still achieve its goal? pls help.

OpenStudy (anonymous):

Do you have any ideas?

OpenStudy (anonymous):

I know we have to divide I think ...

OpenStudy (anonymous):

Right, so, the team will have to win at least three of every 5 games, right? Because 3 wins plus 2 losses is still 5 games played in total. Does that make sense so far?

OpenStudy (anonymous):

Yes it does.

OpenStudy (anonymous):

So you divide the 3 wins out of every 5 games. So you have the expression 3/5. Since there are 20 matches scheduled, you multiply that by 20. So what do you get?

OpenStudy (anonymous):

(3/5)*20 = ?

OpenStudy (anonymous):

12

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

Correct! So, that's how many wins they've got. So that means the rest of the games must have been losses. Do you know how to find the number of losses?

OpenStudy (anonymous):

By dividing?

OpenStudy (anonymous):

No, not by dividing. Remember, you divided the 3 wins out of the 5 games. Think of it like this: out of 20 games, they won 12. If they won 12, how many games are left over for them to have lost?

OpenStudy (anonymous):

@evelyn.xo Well, if it's still unclear, it's 20 - 12. 20 - 12 = ? ? = the number of losses

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