Question

-

Answer 1

b=0, m=2

Answer 2

you want it to be continuous at x=3
and smooth at x=3

so you want x^2=mx+b as x approaches 3
and you want (x^2)'=(mx+b)' as x approaches 3

Answer 3

(x^2)'=(mx+b)' as x approaches 3 means
find the derivative then plug in 3

Answer 4

is the derivatie 2x?

Answer 5

sorry I didn't get a notification

Answer 6

the derivative of x^2 is 2x
and the derivative of mx+b is m

Answer 7

so you have 2x=m as x approaches 3
so m=?

Answer 8

after you find m replace the m in ... "so you want x^2=mx+b as x approaches 3
"
and solve for b

Answer 9

is m=6?

Answer 10

yes m=2*3=6

Answer 11

so now you solve for b:
x^2=6x+b as x approaches 3

Answer 12

so b= -12?

Answer 13

3^2=6(3)+b
9=18+b
I think b is -9

Answer 14

oh I see what you did 3^2 is not 3*2
3^2 is 3*3

Answer 15

thank you!!