Question

electrical engineering math about conversion...MEDAL
3cos600t - 5cos(600t + 20deg)
find the phasor

Answer 1

oh, and the answer is 2.41e^(-j134.8 deg)
but I don't know how to get it

Answer 2

or (2.41∠34.8 deg)
in the old way
Here are similar problems:
http://www.egr.unlv.edu/~eebag/EE-221-Chap%209.pdf#page=10

Answer 3

OK, so from example 16(c) is broken up into real and imaginary parts
then converts from rectangular form to polar...similarly:
3-5e^(j20 deg) is half rectangular form and last part polar...

Answer 4

sob! still not clicking...is it that the Argand diagram--with the one having 90 degs--makes it protrude into the imaginary part of the graph? ...even though it's a visual aid...still...