Question

what is the equation for the axis of symmetry?
what is the equation for the domain?
what is the equation for the range?
what is the equation for the x and y intercepts?

Answer 1

for a parabola

Answer 2

Are you given a parabola or parabolic equation to work with?

Answer 3

no, i just need to know what they are! you can put in a or b as fillers i guess

Answer 4

Let's start, then, with the axis of symmetry. The axis of sym is found by finding the x value, which is found by the equation "x=-b/2a". That value also forms the x value for the vertex. The Y value of the vertex is then found by simply substituting the x value you already have into your equation, and solving for y. The domain in a parabola on it's own is always all real numbers (I believe), and the range, being all the "used" y values, goes from the y value of the vertex (if it opens up) to infinity, or from the y value of the vertex to negative infinity if it opens down. Understand all that?

Answer 5

yes, but the y confuses me
what if the equation was y = (x-5)^2 - 4, what's the equation for x?

Answer 6

Yes, I should have mentioned that. The vertex can be found as I gave it if it's in standard form. However, in the form you just gave me, you'd have to use this formula: \[y=a(x-h)^2+k\]

Answer 7

Where the vertex is expressed as "(h,k)". Just think of them as another name for x and y in a vertex.

Answer 8

The "a" is important, but when it's not given, and with this problem especially, don't worry about it.