The graph of a line passes through the two points (-2, 1) and (2, 1). :/ I'M actually stuck here!!
ummm wait what do i suppose to do there??
Type in your points it gives you the line
well i don't need a line (thx by the way) i actually need to put it in a genral form ..the first time i got it x - y + 1 = 0but my sis says it's wrong :/
Im not fimiliar with that @TheSmartOne
The "General Form" of the equation of a straight line is: Ax + By + C = 0
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AloneS The graph of a line passes through the two points (-2, 1) and (2, 1). :/ I'M actually stuck here!! \(\color{#0cbb34}{\text{End of Quote}}\) First find the slope do you know the slope formula?
i think i don't know the slope :/
this time i've got x + y - 1= 0 am i close to the answer ? :/
\(\sf\Large Slope = \frac{\color{blue}{y_2}-\color{red}{y_1}}{\color{green}{x_2}-\color{purple}{x_1}}\) Where the two points are in the form: \(\sf\Large (\color{purple}{x_1},\color{red}{y_1})~and~(\color{green}{x_2},\color{blue}{y_2})\)
i'm kinda confused ...EH I got 0,1
nah i mean i got (1,)0
what did you get as the slope?
i've got 0 and 1
NVM I GOT IT RIGHT THX :) THX
no problem :)
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