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OpenStudy (anonymous):
\[\frac{ 5 }{ v ^{7} } = \frac{ }{ 3v ^{9} }\]
OpenStudy (anonymous):
Fill in the blank to make equivalent rational expressions.
OpenStudy (daniel.ohearn1):
You had to multiply 5/v^7 by some fractional form of 1 to get something equivalent right?
OpenStudy (anonymous):
yes
OpenStudy (daniel.ohearn1):
What times v^7 is 3v^9 ?
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OpenStudy (anonymous):
i have no ideal
OpenStudy (daniel.ohearn1):
v^a = v^b * v^c
when c+b= a
OpenStudy (daniel.ohearn1):
Does this make sense? This a rule for numbers with exponents.
OpenStudy (anonymous):
i thinl i got it
OpenStudy (daniel.ohearn1):
So what times v^7 will get you v^9 ?
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OpenStudy (daniel.ohearn1):
v*v*v*v*v*v*v multiplied by something with two more vs
OpenStudy (anonymous):
yeah im lost
OpenStudy (daniel.ohearn1):
How about v*v
OpenStudy (anonymous):
v^2
OpenStudy (daniel.ohearn1):
Yes
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OpenStudy (daniel.ohearn1):
So they multiplied by 3v^2
OpenStudy (daniel.ohearn1):
They multiplied the denominator by 3v^2 you see
OpenStudy (daniel.ohearn1):
So what will you do to the numerator if they did that to the denominator in order for fraction to remain equivalent?
OpenStudy (anonymous):
multiply top and bottom
OpenStudy (daniel.ohearn1):
Right you got it then?
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OpenStudy (anonymous):
i will see
OpenStudy (daniel.ohearn1):
What did you get?
OpenStudy (anonymous):
radical 15 i think i did something wrong
OpenStudy (anonymous):
Refer to the Mathematica attachment.
OpenStudy (anonymous):
yeah im lost again
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OpenStudy (daniel.ohearn1):
You multiplied 5*3, that was right, but also the bottom is multiplied by v^2 so the top must also be multiplied by v^2
OpenStudy (daniel.ohearn1):
After that you can simplify
OpenStudy (anonymous):
no solution ?
OpenStudy (anonymous):
Cross multiply and then solve for x.
OpenStudy (daniel.ohearn1):
but in this case, they probably don't won't you to simplify... They just want the blank.. So what is 5*3v^2?
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OpenStudy (anonymous):
5(3 v^9) = x v^7
OpenStudy (anonymous):
15v^2
OpenStudy (anonymous):
The numerator on the RHS is 15 v^2
OpenStudy (daniel.ohearn1):
So that's your answer. Notice that the fraction was then multiplied by (3v^2/3v^2) or 1 so the fractions are equivalent although they are represented differently?