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16?
u sure?
how did u get it?
f(x)={(x-1)^2,x<-1; 2x-3 , x>1} x = -3 -3<-1 sooooo (-4)^2=16
thanks
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A piece-wise function is the connection of two functions for any determined region of the plane, in this case, where the pattern of the dependant variable respective to the independant variable changes. You can also read it as: \(f\) is defined by \(f(x)=(x-1)^2\) when x is less than -1 and \(f(x)=2x-3\) when x is greater than -1. Now, since we want to find \(f(-3)\) we have to note that -3<-1 therefore it falls on the piece function: \[f(x)=(x-1)^2\]
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