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The amount of potential energy, P, an object has is equal to the product of its mass, m, its height off the ground, h, and the gravitational constant, g. This can be modeled by the equation P = mgh. What is the equivalent equation solved for h?
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pmg=H for D.
Okay, look at the given equation : \[P = mg\color{red}{h}\]
what operation must you do to both sides of that equation in order to get \(\color{red}{h}\) isolated, all by itself ?
the last one?
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pmg=h
g is not constant h = P/mg
Nope. Divide \(mg\) both sides : \[\dfrac{P}{mg} = \dfrac{mg\color{red}{h}}{mg}\]
oh so the first one..
Yep!
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