Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is
89m
long and
66m
wide.
Find the area of the training field. Use the value
3.14
for
π
, and do not round your answer. Be sure to include the correct unit in your answer.

Answer 1

Total area =area of rectangular part+ area of two semicircular part
= area of rectangle+area of circle
(Two semicircular=one circle)

Answer 2

Could u give the image please? Thanks

Answer 3

And diameter of circle= width of rectangular part
So radius =width /2

Answer 4

@Pawanyadav and @spiderghost12 I understand how to work the problem out i'm just not sure of how i need to go about finding my final answer. And sorry but for some reason it isnt letting me upload the pic :( I would just use the numbers to help you with the problem.

Answer 5

@Pawanyadav You aren't making any sense to me.. sorry but I know that you take 89 and multiply it by 66 and then you you divide 66 by 2 and then multiply 3.14 times the number is gives you. Then, you will see if you need to add or subtract from there or divide that number by 2 again to get your final answer.

Answer 6

Area =length ×width +π(width/2)^2

Answer 7

Thank you so much I have a couple more to do so if you could help me with a few more after till I get it right that would be great!!

Answer 8

Welcome

Answer 9

How long will it take you to find the answer?

Answer 10

Area=89×66 +3.14(33)^2
Calculate yourself

Answer 11

You know rules of open study

Answer 12

this isn't a test problem this is a practice problem

Answer 13

thank you so much that was right could you help me do that with a couple more?

Answer 14

I will fan you and give you a medal

Answer 15

=5874+3419.46=9293.46

Answer 16

A rectangular piece of paper with length
34cm
and width
14cm
has two semicircles cut out of it, as shown below.
Find the area of the paper that remains. Use the value
3.14
for
π
, and do not round your answer. Be sure to include the correct unit in your answer.

Answer 17

This is my new problem i am working on

Answer 18

Same everything
Just this time you have to subtract area of circle from area of rectangle.

Answer 19

so 34 * 14 -3.14(7)^2?

Answer 20

Correct

Answer 21

A rectangular paperboard
29in
long and
22in
wide has a semicircle cut out of it, as shown below.
Find the area of the paperboard that remains. Use the value
3.14
for
π
, and do not round your answer. Be sure to include the correct unit in your answer.

Answer 22

what about this one? Add or subtract?

Answer 23

Btw i just tried subtracting and adding it didnt work

Answer 24

Subtract but this time it's not a circle
It's only a semicircle. So
Area=length ×width-(π11^2)/2

Answer 25

Area of circle /2

Answer 26

so what would that look like plugged in?

Answer 27

I got it!!

Answer 28

Area=29×22-π(11^2)/2
=638-189.97=448.03

Answer 29

A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is
23ft
long and
16ft
wide.
Find the area of the garden. Use the value
3.14
for
π
, and do not round your answer. Be sure to include the correct unit in your answer. This one?

Answer 30

Previous question but add this time

Answer 31

would it be 568.96? or would i divide it by 2?

Answer 32

I need to go ...can't help more.
Area=23×16+π(8^2)/2

Answer 33

Okay then??? Thanks for the help anyways!!

Answer 34

You are welcome

Answer 35

I need to go ...can't help more.
Area=23×16+π(8^2)/2

Answer 36

Previous question but add this time

Answer 37

468.48?