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Mathematics 7 Online
Hayhayz (hayhayz):

http://prntscr.com/99lht7

Hayhayz (hayhayz):

@ZakkDanger @misty1212

OpenStudy (misty1212):

same as before (HI AGAIN!!)

OpenStudy (misty1212):

set the denominator equal to zero and solve

OpenStudy (misty1212):

let me know when you get \(x=1\)

Hayhayz (hayhayz):

yes i did that, how do you find the zeros?

OpenStudy (misty1212):

set the numerator equal to zero and solve

OpenStudy (zakkdanger):

FUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUK

OpenStudy (misty1212):

lol

OpenStudy (misty1212):

\[3x^2+x-4=0\\ (x-1)(3x+4)=0\] we have taken care of the \(x-1\) already, set \[3x+4=0\] get \[x=-\frac{4}{3}\]

Hayhayz (hayhayz):

WOW. you make it look so much easier than the lesson i read. THANK YOU

OpenStudy (misty1212):

lol it is all easy when you know how!

OpenStudy (zakkdanger):

Lol your so fast to answer misty1212

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