http://prntscr.com/99lht7
@ZakkDanger @misty1212
same as before (HI AGAIN!!)
set the denominator equal to zero and solve
let me know when you get \(x=1\)
yes i did that, how do you find the zeros?
set the numerator equal to zero and solve
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lol
\[3x^2+x-4=0\\ (x-1)(3x+4)=0\] we have taken care of the \(x-1\) already, set \[3x+4=0\] get \[x=-\frac{4}{3}\]
WOW. you make it look so much easier than the lesson i read. THANK YOU
lol it is all easy when you know how!
Lol your so fast to answer misty1212
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