Question

Find the factored form of 2x3 – 4x2 – 6x.

2x(x2 – 2x – 3)

2(x2 + 1)(x – 3)

x(2x + 1)(x – 3)

2x(x + 1)(x – 3)
@amistre64

Answer 1

2x(x2 -2x-3)

Answer 2

what's the common numerical factor? Factor that out. What's the common literal (letter) factor? Also factor that out. What's left? Factor this trinomial.

Answer 3

Using the AC method -> 2x(x−3)(x+1)

Answer 4

x

Answer 5

2x(x+1)(x−3) sorry

Answer 6

i think it is d is that right @mathmale

Answer 7

Before answering that particular question, I need to see your work.

Answer 8

2x(x + 1)(x – 3)
2x(x^2-2x-3)
2x^3-4x^2-6x

Answer 9

If your factors take you back to the original expression, then yes, you are correct. :)

Answer 10

Yes you factor out your gcf and that would be a 2x(x2-2x-3x) remember always check to see if you can factor out gcf next you use the ac method what is you A times your C it is -3 now you need to find something that multiply to give you your ac that is -3 and adds to give you your b that is -2. Then you right out -2 under it you right 1 and 2 now you figure out what needs to be a positive and a negative in this case they are both negative numbers your next line would be 2x(x2-1x-2x-3) now you group them so that looks like 2x[x(2-1)(x-3) now you re write it to look like 2x(x+1)(x-3)