Question

I don't really remember how to solve this can someone help walk me through it?
2x^2=-7x+4
I need to solve by factoring..

Answer 1

Ok basically first we need to put the equation into standered form which looks like this:
\[\huge~\rm~\bf~ax^2+bx+c=0\]
Can you you do that please?

Answer 2

Okay If I do that I get 2x^2+7x-4=0

Answer 3

Ok good
\[\huge~\rm~\bf2x^2+7x−4=0\]
Lets use factor by grouping method

Answer 4

So what is
\[\huge~\rm~-4 \times 2=? \]

Answer 5

-8

Answer 6

Good the 7 remains the same now we have

Answer 7

what NUMBERS multiply to -8 but add/subtract to make 7?

Answer 8

-7 & -1

Answer 9

Nevermind. I did that backwards

Answer 10

Those 2 aren't right
-7 x -1=7
-7-1=-8

Answer 11

8 & 1

Answer 12

Good almost there
it would be
8 and -1

Answer 13

Yup! (:

Answer 14

7x has been split into -1 and 8
now our equation looks like this
\[\huge~\rm~\bf2x^2-1+8x-4\]

\[\huge~\rm~\bf(2x^2-1)(8x-4)\]

We need to find a common factor for both of these

Answer 15

When I factored it out I got (2x-1)(x+4)

Answer 16

That's the correct answer :)

Answer 17

So now I just set them each to zero and I should have both zeros right?