I don't really remember how to solve this can someone help walk me through it?
2x^2=-7x+4
I need to solve by factoring..
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pooja195 (pooja195):
Ok basically first we need to put the equation into standered form which looks like this:
\[\huge~\rm~\bf~ax^2+bx+c=0\]
Can you you do that please?
OpenStudy (anonymous):
Okay If I do that I get 2x^2+7x-4=0
pooja195 (pooja195):
Ok good
\[\huge~\rm~\bf2x^2+7x−4=0\]
Lets use factor by grouping method
|dw:1449099787708:dw|
pooja195 (pooja195):
So what is
\[\huge~\rm~-4 \times 2=? \]
OpenStudy (anonymous):
-8
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pooja195 (pooja195):
Good the 7 remains the same now we have
|dw:1449099901099:dw|
pooja195 (pooja195):
what NUMBERS multiply to -8 but add/subtract to make 7?
OpenStudy (anonymous):
-7 & -1
OpenStudy (anonymous):
Nevermind. I did that backwards
pooja195 (pooja195):
Those 2 aren't right
-7 x -1=7
-7-1=-8
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OpenStudy (anonymous):
8 & 1
pooja195 (pooja195):
Good almost there
it would be
8 and -1
OpenStudy (anonymous):
Yup! (:
pooja195 (pooja195):
7x has been split into -1 and 8
now our equation looks like this
\[\huge~\rm~\bf2x^2-1+8x-4\]
\[\huge~\rm~\bf(2x^2-1)(8x-4)\]
We need to find a common factor for both of these
OpenStudy (anonymous):
When I factored it out I got (2x-1)(x+4)
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pooja195 (pooja195):
That's the correct answer :)
OpenStudy (anonymous):
So now I just set them each to zero and I should have both zeros right?