Solve the system using substitution. x + y = 8 y = 3x
look for x+y=8 for y we put 3x and it means that x +3x=8 4x=8 x=2
why?
we know that y= 3x in another equation we only put not y but this 3x, that all that you need to do
But x + 3x = 8 isn't an answer choice.
Okay, isolate a variable to one side of the equation. For instance:\[x + y = 8 \]Isolate:\[y=8-x\] Substitute y into the other equation! :) \[8 - x =3x\]Add x. \[8=4x\]Divide.\[2 = x\]
Is that easier to understand?
I dont understand.
Substitute 3x for y x + 3x = 8 Add the x's 4x = 8 Divide by 4 to get the x by itself x = 2 Plug 2 into the bottom equation for x y = 3(2) Multiply y = 6 Your answers: x = 2 y = 6
you understood?
Look at the two equations you have. x + y = 8 y = 3x In the first equation x + y = 8, I moved x by subtracting it by both sides. So.. y = 8 - x <--- REPLACE Y IN THE OTHER EQUATION WITH THIS. Now SUBSTITUTE Y. LOOK AT YOUR SECOND EQUATION NOW. y = 3x ^ | 8 - x = 3x Add x. 8 = 4x Divide 4 by both sides. 2 = x
@trenten 3 + 1
lol yeah I understand now. Thanks
^ ^ .
what? how was that hurtful? I said yours was the Best Response.. uh okay?
how am I wrong?
Being sarcastic, do enjoy your evening.
weird. okay.
If there's no other clarifying question, don't forget to close out. Though, it's at your discretion.
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