Hello Can somebody check an answer for me about finding consecutive integers please? :( :D
Ok so i was given an explanation but it was wrong
he meaning of consecutive means continuous {please don't be offended } so let the first term be 'y', the second one be 'y+1' and the third one be 'y+2' so according to the question, y+(y+1)+(y+2)=21 you don't need to worry as there is a '+' sign outside the bracket you just need to add = y+y+1+y+2=21 group the like terms [terms with same ending like 'y'] = y+y+y+1+2 =21 3y+3=21 {just to tell you y*y*y= y³ } now 3y=21-3 3y=18 y=18/3 y=6 so the integers are y=6, y+1=6+1=7 and y+2= 6+2=8 if you want to check=6+7=13+8=21 hence proved
Somehow this is wrong and it was incorrect
Three consecutive odd integers have a sum of 21. Find the integers.
^thats the question
the answer 6, 7, and 8 was wrong
@escamer :D
@KendrickLamar2014
sorry :( i dont know this but kendrick will
its okay :)
@sleepyjess
@IrishBoy123 can you see what is wrong :(
Three consecutive ***odd*** integers
they are 2 apart on the number line
Im so confused tho. I didnt even know how to do it myself.
soz, you've lost me now if they are odd, they are 2 apart on the number line so it is n + (n + 2) + ((n + 2) + 2) = .......
lol i guess ill leave this topic and do another one because I cant
well, do come back when you are ready i though you could already do the *consecutive* number problem the *consecutive* **odd** number problem is just an extension
@ZacharySanders please dont stand by people's questions for no reason Its VERY irritating for like idk how many hours now :/
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