Question

Need a refresher on a few problems..

Answer 1

Find and simplify the difference quotient f(x+h)-f(x) over h , h=/0 for the given function.

f(x)=x^2 +4x+5

Answer 2

I got 2x+h+4.

Answer 3

(2,5) perpendicular to the line y-1/6x +8

Answer 4

I got y=-1/6x -17/6

Answer 5

@IrishBoy123

Answer 6

post/scan/link/draw the original question if you can, pls.

then i can try help :p

Answer 7

for perpendicular lines, following general equation \(y = mx + c\). we know that \(m_1 m_2 = -1\)

Answer 8

Yeah..

Answer 9

yeah....

work it from there

Answer 10

y-5= -1/6(x-2)

Answer 11

Note what is posted: m1*m2=−1
so -1/6 is not the right slope....

Answer 12

Oh my gosh -.-

Answer 13

Okay starting over now..
y-5=-6/1(x-2)

Answer 14

Answer- y=-6x+17

Answer 15

correct :)

Answer 16

Okay. Cannot believe I did that

Answer 17

Next question..

Answer 18

Use the graph of the function f, plotted with a solid line, to sketch the graph of the given function g.
g(x)= -f(x+2)-2
y=f(x)

Answer 19

I know -f causes it to be flipped.. But I cant remember if (x+2) is vertical or horizontal.. I think horizontal :/

Answer 20

make sense?

Answer 21

Uh no

Answer 22

Are you saying (x+2) is the vertical shift?

Answer 23

notice the expression x+2 will just move everything sideway by +2