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Physics 18 Online
OpenStudy (tacomaco90):

closed

OpenStudy (tacomaco90):

@AlexandervonHumboldt2

OpenStudy (irishboy123):

try putting a few numbers in if you cannot follow the maths of the equation

OpenStudy (tacomaco90):

I did but i still do not understand

OpenStudy (anonymous):

Can you post a screenshot of the question or fully write it out for us?

OpenStudy (michele_laino):

If the independent variable is the velocity \(v\), then the grpah which represents the relation: \(f(v)=mv^2/r\) is a quadratic parabola, namely a non-linear graph. In such formula, the distance \(r\) is considered as a simple parameter, so, more precisely, we can write this: \(f_r(v)=mv^2/r\)

OpenStudy (michele_laino):

oops..I meant ...the graph*...

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