Question

2x^2 -3x=x^2+10
solve by factoring

Answer 1

Any ideas?
:-)

Answer 2

2x^2-3x=x^2+10
2x^-x^2=10+3x
x^2=10+3x
x=5

Answer 3

i am right?

Answer 4

i think there should be two answers for x..

Answer 5

i think they want you to move it into standard form first

y = ax^2 + bx + c = 0

Answer 6

x^2 - 3x - 10 = 0

(x )*(x ) = 0

Answer 7

ok guys) i will try to do for this formula)

Answer 8

(x-5)(x+2)

Answer 9

use factors of 10 to try and create a -3 in the middle

Answer 10

+2 and -3

Answer 11

put those in and expand to see if it worked..

(x + 2)*(x - 3) = 0

Answer 12

oh okay thanks guys!!! :)

Answer 13

welcome, so either of those ( ) can be zero to make it true, x=-2 or x = 3

Answer 14

or you can always apply the quadratic formula and see what th evalues are to give a hint as to the factors

Answer 15

thank you very much