Question

-4(x+5)^2 +11 = -245
Solve quadratic function with square roots

Answer 1

do you understand how to solve these type of questions ?
thats the same as last one
what would be the first step ?

Answer 2

Simplify it into the form ax^2 + bx + c = 0

Answer 3

by mentions this `with square roots` i don't think they wants em to foil (x+5)^2

you can take square root both sides to cancel out the square but in order to do that you need to get rid of everything except (x+5)^2 at left side

Answer 4

okay this is new to me "with square roots"
so let's subtract 11 from both sides

Answer 5

-4(x+5)^2 =256 right then take the square root of both sides

Answer 6

recall a square root is the same as raised to 1/2 power

\[\sqrt{a}=a^{1/2}\]

Answer 7

first isolate what is being squared by itself, by dividing both sides by (-4)

Answer 8

(x+5)^2 = 64

Answer 9

-2(x+5) =16
x+5 = -8
x = -13 this might be wrong so follow DanJS 's path

Answer 10

then remember for a square root of something squared, results in an absolute value

\[\sqrt{(x+5)^2}= \left| x+5 \right|\]

Answer 11

so you end up with

\[\left| x+5 \right|=8\]

Answer 12

to solve those , the absolute value term can equal + or - 8

x+5=+8
or
x+5=-8


x has 2 values