State the domain and range of the relation y=arccos x.
Please no direct answers. Thanks.
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OpenStudy (danjs):
first, what is the domain/range for y=cos(x)
OpenStudy (haleyelizabeth2017):
The domain is all real numbers?
OpenStudy (haleyelizabeth2017):
And the range is −1 ≤ y ≤ 1...
OpenStudy (danjs):
yes
OpenStudy (danjs):
the arccos is the inverse function... the range of cos(x) will become the domain of arccos(x)
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OpenStudy (haleyelizabeth2017):
Okay
OpenStudy (danjs):
y = cos(x)
------
y = arccos(x)
cos(y) = x
inverse
OpenStudy (danjs):
domain and range of x = cos(y)
domain, x is -1 to 1,
OpenStudy (danjs):
range resulting from that domain
cos(y) = -1 at y=pi
to
cos(y)=1 at y = 0
range 0 to pi
OpenStudy (danjs):
you have to restrict the cosine functions domain , in order to take its inverse
cosine is not 1-to-1 function, unless you only take the restricted domain..
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OpenStudy (haleyelizabeth2017):
Okay, thanks
OpenStudy (danjs):
inverse is a reflection over line y=x, you can only do that if you take the restricted domain on cos(x) from 0 to pi/2
that is why the inverse cosine is just that one section