1.Write the equation of a line that is perpendicular to the given line and that passes through the given point. y-3=8/3(x+2); (-2, 3) A.y+3=-3/8(x-2) B.y-3=-3/8(x+2) C.y-2=-3/8(x+3) D.y+3=3/8(x-2)
2.Describe how the graph of y=/x/ and y=/x+3/ are related. A.The two graphs are the same B.The graphs have the same shape. The y-intercept of y=/x/ is 0, and the x-intercept of the second graph is 3. C.The graphs have the same shape. The y-intercept of y=/x/ is 0, and the y-intercept of the second graph is 3. D.The graphs have the same shape. The y-intercept of y=/x/ is 0, and the y-intercept of the second graph is -3.
1. First, isolate the slope of the given equation. What must you do to the slope of the given equation in order to make a perpendicular slope for the second line equation? Solve for the 2nd slope. Now that you have the 2nd slope, and a point on the 2nd line, use point-slope form to find an equation for the 2nd line.
2. Which choices can you eliminate immediately?
I think 1 is B and 2 is D. am I correct? @dimensionx
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